7+22/y+3/y^2=0

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Solution for 7+22/y+3/y^2=0 equation:


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

22/y+3/(y^2)+7 = 0

22*y^-1+3*y^-2+7 = 0

t_1 = y^-1

3*t_1^2+22*t_1^1+7 = 0

3*t_1^2+22*t_1+7 = 0

DELTA = 22^2-(3*4*7)

DELTA = 400

DELTA > 0

t_1 = (400^(1/2)-22)/(2*3) or t_1 = (-400^(1/2)-22)/(2*3)

t_1 = -1/3 or t_1 = -7

t_1 = -7

y^-1+7 = 0

1*y^-1 = -7 // : 1

y^-1 = -7

-1 < 0

1/(y^1) = -7 // * y^1

1 = -7*y^1 // : -7

-1/7 = y^1

y = -1/7

t_1 = -1/3

y^-1+1/3 = 0

1*y^-1 = -1/3 // : 1

y^-1 = -1/3

-1 < 0

1/(y^1) = -1/3 // * y^1

1 = -1/3*y^1 // : -1/3

-3 = y^1

y = -3

y in { -1/7, -3 }

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